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MATHS MAINS 2017 , HOW WAS THE EXAM ? and Expected marks ( those which are sure shot correct )

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Comments

  • Aks11Aks11
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    dim(UnW) 4 nhi ho sakta coz then U= W as dim of U , W and UnW are all 4 and ques mein distinct U and W diya hai.
    toh dim(UnW) can be 3 or 2 only.
  • mayank_mmayank_m
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    dim(UnW) 4 nhi ho sakta coz then U= W as dim of U , W and UnW are all 4 and ques mein distinct U and W diya hai.
    toh dim(UnW) can be 3 or 2 only.
    hmm missed the distinct part. Pata nahi aise aur kitne mistakes kiye hai maine paper me :neutral:
  • vaibhav_19vaibhav_19
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    dim(UnW) 4 nhi ho sakta coz then U= W as dim of U , W and UnW are all 4 and ques mein distinct U and W diya hai.
    toh dim(UnW) can be 3 or 2 only.
    hmm missed the distinct part. Pata nahi aise aur kitne mistakes kiye hai maine paper me :neutral:
    maths me ye he to dikat he salla! binary me marks ne dete ho bas. Either 1 or 0
  • mayank_mmayank_m
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    dim(UnW) 4 nhi ho sakta coz then U= W as dim of U , W and UnW are all 4 and ques mein distinct U and W diya hai.
    toh dim(UnW) can be 3 or 2 only.
    hmm missed the distinct part. Pata nahi aise aur kitne mistakes kiye hai maine paper me :neutral:
    maths me ye he to dikat he salla! binary me marks ne dete ho bas. Either 1 or 0
    mujhe aisa lag raha hai maine ye consider kara tha exam me and ans 2,3 hi aaya tha par ab sure nahi hu :disappointed:
    aisa lag raha hai ab acche se 2018 ki tayari start kar hi deni chaiye
  • RaniGaidinliuRaniGaidinliu
    Maths me dekhna Dhoka nahi hoga..sabke average ya slightly upar aa jayenge..
    Essay ethics me acche aaye to Nikal loge
  • mathematics.optional@gmail.commathematics.optional@gmail.com
    did anyone solve the question where u have to show that sinx/x is absolutely divergent?
    i did...its given as solved eg in shanti narayan
    Bro can u please upload snapshot of the answer page..I cants find in the book
  • wrong_passwordwrong_password
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    10 marks ke liye itna hi karna hai..ya phir koi random subspace of given dimension man kar ke show karna hai ??
  • wrong_passwordwrong_password
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    dim(UnW) 4 nhi ho sakta coz then U= W as dim of U , W and UnW are all 4 and ques mein distinct U and W diya hai.
    toh dim(UnW) can be 3 or 2 only.
    10 marks ke liye itna hi karna hai..ya phir koi random subspace of given dimension man kar ke show karna hai ??
  • wrong_passwordwrong_password
    Ye mains 2016 ka h..3 marker..
  • saimadhavsaimadhav
    how to solve this question:
    mains- 2017 (mathematics), paper-1 , question no- 2 (d)

    regarding dimension of subspace U intersection W
    dim(U intersec W) = dim(U) + dim(W) - dim(U+W) = 8 - dim(U+W)
    U is a subset of U+W and U+W is a subset of V, Thus possible values of dim(U+W) = 4,5,6

    Thus possible values of dim(U intersec W) = 4,3,2
    10 marks ke liye itna hi karna hai..ya phir koi random subspace of given dimension man kar ke show karna hai ??
    thats it. solution from schaum for same question
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