MATHS MAINS 2017 , HOW WAS THE EXAM ? and Expected marks ( those which are sure shot correct )

Catman

anyone?

p2 2017

Let w1 and w2 be two solutions of the given pde.

Then, u = w1 - w2 satisfies the laplace eq. with boundary condition u = 0 on the closed curve.

Now, Del^2(u) = 0 in S and u = 0 on curve (gamma)

But u can take maximum and minimum values only on the boundary (using max/min principle) => u is identically 0 in S

Therefore, w1 - w2 = 0 in S => w1 = w2

Bhai ye kahan se padha? Koi reference book?

wrong_password

2016 , paper-1
final answer..anyone pls ?

Hybrid

anyone?

Bhai ye kahan se padha? Koi reference book?

Internet research!

Look for uniqueness of solutions of Poisson eq. Ab poisson to syllabus mein hai ni par solution is based more on laplace eq.

Exam mein well-left hi ki thi isko

rahulsri

2016 , paper-1
final answer..anyone pls ?

My answer [-2,-2,-4 ; 0,2,4 ;3,-2,1]

wrong_password

are koi hai kya ? itna sanatta ??

vaibhav_19

Happy new year fellow mates. May our equation of continuity be sustained at all the points this year irrespective of how tough the boundary conditions get we will be able to find constants in our life to fall back upon to ensure that our equation of motion is satisfied always. Moments of inertia would surely come but let's promise we won't let it interpolate by any of the methods.
It is only when an aspirant(function) is continuous that he is able to differentiate from others. But someone who is not continuous would never be able to differentiate himself from the crowd.

#Paper2

googler

Happy new year fellow mates. May our equation of continuity be sustained at all the points this year irrespective of how tough the boundary conditions get we will be able to find constants in our life to fall back upon to ensure that our equation of motion is satisfied always. Moments of inertia would surely come but let's promise we won't let it interpolate by any of the methods.
It is only when an aspirant(function) is continuous that he is able to differentiate from others. But someone who is not continuous would never be able to differentiate himself from the crowd.

#Paper2

Happy new year Bhai. p2 ki gatha ko Kya Kavita banaya Maja aa gya...

Vrikodara

How to solve this one.. at least tell me from which section it has come from the complex analysis... and also share the approach... m getting no clue...

Interesting...

f is entire => f' is entire => fn is entire and hence analytic

But given that the zeros of fn are 1,1/2,1/3... => non-discrete set => fn is identically zero => f is a polynomial

seem right?

How did you get this step?
But given that the zeros of fn are 1,1/2,1/3... => non-discrete set => fn is identically zero

rahulbn92

just one question future collectors. I was scoring more than 425 in all of IMS test series papers but hardly scoring 200 (250 correct) in mains. i was following Krishna series for most of the topics like any other aspirant. Can you tell me what went wrong and what should be future strategy. Thanks in advance

Krk_returns

I attempted 300 marks in paper 1 by mistake.
How is my copy going to be checked?