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@googler well that is condition for trapezoidal rule, but the question is how many intervals we can take 2 intervals, 4 intervals, 6 intervals, 8 intervals etc how to decide
Trapezoidal rule ke error formula main 'h' aata hai. Its h^2 i think. Use error given in question to find value of h. (h = interval length)
@googler well that is condition for trapezoidal rule, but the question is how many intervals we can take 2 intervals, 4 intervals, 6 intervals, 8 intervals etc how to decide
Trapezoidal rule ke error formula main 'h' aata hai. Its h^2 i think. Use error given in question to find value of h. (h = interval length)
h^3/12 < 5x10^-5 by solving we get h < 0.84 s0mething so if we take no of dvisions = 12 then h = 1/12 = 0.8333 this way we have proceed..
I think there were 2 wrong question.. simplex wala and other one is max/min value of x2 + y^2 + z^2 simplex wale me third equation me < 10 hona chahiye as per standard book LPP Krihsna series..snapshot attahched..qustion me <0 diya h.. mx/min wale question me 2nd condition diya hi ni (OMG).. which is z= x+y..this is very standard question which we might have solved/seen many times..again spans from Malik n Arora attached.. plz lemme me know if i am wrong.. simplex wale me kya answer aaya...
Paper 2 , question 3b is correct. It can be done by Lagrange method of multipliers.
X=0, y=0, z=0 comes from that equation. Put x=0, y=0 in equation of ellipsoid. That gives point (0,0,+- 5). Similarly other points comes as (+-2,0,0) and (0,+- root 5,0).
From these points max and min value comes as 25 and 4.
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Comments
I found paper 2 very lengthy.... scaling pattern kya Hota hai ifos me.
(h = interval length)
by solving we get h < 0.84 s0mething
so if we take no of dvisions = 12 then h = 1/12 = 0.8333
this way we have proceed..
simplex wale me third equation me < 10 hona chahiye as per standard book LPP Krihsna series..snapshot attahched..qustion me <0 diya h..
mx/min wale question me 2nd condition diya hi ni (OMG).. which is z= x+y..this is very standard question which we might have solved/seen many times..again spans from Malik n Arora attached.. plz lemme me know if i am wrong.. simplex wale me kya answer aaya...
It can be done by Lagrange method of multipliers.
X=0, y=0, z=0 comes from that equation.
Put x=0, y=0 in equation of ellipsoid. That gives point (0,0,+- 5). Similarly other points comes as (+-2,0,0) and (0,+- root 5,0).
From these points max and min value comes as 25 and 4.